Geometry math question Please help
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6x+24=10x
or 10x-6x=24
or 4x=24
therefore x=24÷4=6
therefore angle BEK=6x+24+10x
=36+24+60
=120 degree ans
or 10x-6x=24
or 4x=24
therefore x=24÷4=6
therefore angle BEK=6x+24+10x
=36+24+60
=120 degree ans
Answered by
1
given :
in triangle c b e and triangle c k e
angle c = c angle b = k angle e = e
:: angle c + angle b + angle e = angle c + angle k+ angle e
( angle c -angle c) + (angle b -angle b ) +( angle e -angle e) = 0
so :: ( 6x + 24) - 10x = 0
(-4x +24) = 0
X = -24/-4
X = 6
NOW angle BEK = 6X+24+10X
= 6 * 6 + 24 + 10 * 6
= ""120""
I THINK IT IS HELP FULL FOR U SO PLS THANK ME
in triangle c b e and triangle c k e
angle c = c angle b = k angle e = e
:: angle c + angle b + angle e = angle c + angle k+ angle e
( angle c -angle c) + (angle b -angle b ) +( angle e -angle e) = 0
so :: ( 6x + 24) - 10x = 0
(-4x +24) = 0
X = -24/-4
X = 6
NOW angle BEK = 6X+24+10X
= 6 * 6 + 24 + 10 * 6
= ""120""
I THINK IT IS HELP FULL FOR U SO PLS THANK ME
jerom76:
This for detail answer
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