Question

GEOMETRY
Q.9 The width of the rectangle is 2/3 of its length. If the perimeter of the
rectangle is 80 cm. Find its area.​

Answer 1

Step-by-step explanation:

Let the length be x

so, the breadth is 2x/3

given that the perimeter is 80 cm

perimeter of a rectangle=2(l+b), substituting the values,

2(x+ 2x/3) =80 (1)

dividing (1) by 2

x + 2x/3=40

5x/3=40, By cross-multiplication,

5x=120

x=120/5

x=24cm

So the length of the rectangle is 24cms

Breadth=2/3 × 24= 16 cms

Area of a rectangle=L×B

Substituting the values of L and B,

Area=24×16=384 cm2

Hope it helps!

Answer 2

Answer:

Let the length be xso, the breadth is 2x/3given that the perimeter is 80 cmperimeter of a rectangle=2(l+b), substituting the values, 2(x+ 2x/3) =80 (1) dividing (1) by 2x + 2x/3=405x/3=40,

By cross-multiplication, 5x=120x=120/5x=24cmSo the length of the rectangle is 24cmsBreadth=2/3 × 24= 16 CMS Area of a rectangle=L×BSubstituting the values of L and B, Area=24×16=384 cm2