Question

George can do some work in 8 hours. Paul can do the same work in 10 hours while hari can do the same work in 12 hours. All the three of them start working at 9 am. While george stops work at 11 am,the remaining two complete the work,approximately when will the work be finished?

Answer 1

Answer: 1:55 pm

Step-by-step explanation:

George - 8

Paul      - 10

Hari       - 12

LCM of 8,10,12 = 120

George does work in 1 hour = 15

Paul " " " " " "" " " "" " " "" " " " = 12

Hari " " "" " "" " " " "" " " " "" " "= 10

All worked for 2 hrs

Total work done in 2 hours = 37*2 = 74

Left work  =  46

Work done Paul and hari in 1 hour = 22

Time taken to complete work = 46/22 = 23/11 = approx 2 hours 55min

Time whe work completed = 1:55pm     (after adding 4 hrs 55min to 9 am)