Question

George can do some work in 8 hours. Paul can do the same work in 10hours while Hari can do the same work in 12 hours. All the three of themstart working at 9 a.m. while George stops work at 11:00 a.m., theremaining two complete the work, approximately when will the work befinished?

Answer 1

Answer:

13:06 p.m

Explanation:

George- 8 hrs, Paul- 10 hrs, Hari- 12 hrs

They start at 9 a.m

George stops at 11 a.m.

Work finsh time=?

Let's find speed of each:

George- can complete 1/8 of work in an hour. He works 2 hrs and completes 2*1/8=1/4 of work

Paul- can complete 1/10 of work in an hour

Hari- can complete 1/12 of work in an hour

Since George has left by completing 1/4 of work, remaining work is 3/4.

Paul and Hari complete 1/10+1/12= 11/60 of work in an hour together.

Remaining work will be completed in:

3/4:11/60=45/11= 4 1/11 hours counting from 9 a.m as we already considered work done by George.

So 9 a.m + 4 1/11 hrs≈13 hrs 06 min

Work will be finished approx. at 13:06 p.m

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