Question

George does 3/5th of a piece of work in 9 days. He then calls paul. And they finish the work in 4 days. How long would paul take to do the work by himself?

Answer 1

paul would finish this work in 30 days...

Answer 2

Answer: The value of x $=\dfrac{60}{11}=5\dfrac{5}{11}$

Step-by-step explanation:

Since we have given that

George does $\dfrac{3}{5}^{th}$ of a piece of work = 9 days

George does 1 unit of piece of work in = $\dfrac{9}{\dfrac{3}{5}}\\\\=\dfrac{9\times 5}{3}\\\\=3\times 5\\\\=15$

According to question, then Paul came and they altogether finishes the work in 4 days.

Let the number of days Paul alone can finish the work be 'x'.

So, it becomes,

$\dfrac{1}{15}+\dfrac{1}{x}=\dfrac{1}{4}\\\\\dfrac{1}{x}=\dfrac{1}{4}-\dfrac{1}{15}\\\\\dfrac{1}{x}=\dfrac{15-4}{60}=\dfrac{11}{60}$

Hence, the value of x $=\dfrac{60}{11}=5\dfrac{5}{11}$