Question

George passed one sixth of his life in childhood, one twelfth in youth, and one seventh more as a bachelor; five years
after his marriage a son was born who died four years before his father at half his final age. How old is George?
LETE
O 60 years
LETE
84 years
45 years
O 78 years

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer: 84

Step-by-step explanation: Here is the solution in details:

Say father's age is x,and son's age is y.we have two variables.We have two equations also.As son's age is half the father's age.So y=x/2 or

x=2y---------------(1)

Now you can read the question like this also.

Next father has spent x/6th of his life in child hood,x/12th of his life as youngster and x/7th of his life as a bachelor,then 5yrs of marriage,then had a son,then son dies,after 4yrs father dies.It gives us this following equation.

x/6+x/12+x/7+5+y+4 = x -------------(2)

Solving (1) & (2) the equations:

=> Y=42

=> X=84