Physics, asked by archanamondal5138, 9 months ago

George walks 36 kms partly at a speed of 4 kms per hour and partly at 3 km per hour if he had walked at a speed of 3km per hour when he had walked at 4 and 4 km per when he had walked at 3 he would have walked only 34 kms. The time (in hours) spent by george in walking was).

Answers

Answered by amitnrw
0

Answer:

10 hrs

Explanation:

Let say T₁ & T₂ were the time for different Speed

Distance = Speed * Time

4T₁  + 3T₂  = 36   - eq 1

3T₁ + 4T₂  = 34      eq 2

4*eq 1 - 3* eq 2

16T₁ - 9T₁ = 4*36 - 3*34

=> 7T₁ = 42

=> T₁ = 6

4*6 + 3T₂  = 36

=> 3T₂ = 12

=> T₂ = 4

T₁ + T₂ = 6 + 4 = 10  hr

10 hrs time spent in walking

Answered by raj8125592345
0

Answer:

speed of 4 kms per hour and

George walks 36 kms partly at a speed of 4 kms per hour and partly at 3 km per hour If he had walked at a speed of 3km per hour when he had walked at 4 and 4 km ...

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