Question

Georgia is jogging with a velocity of 4 m/sec when she accelerates at 2 2 m / sec for 3 seconds.
How fast is Georgia running now?​

Answer 1

Given :-

Georgia is jogging with a velocity of 4 m/sec when she accelerates at 22 m/s² for 3 seconds.

To find :-

How fast is Georgia running now

Solution :-

• Initial velocity = 4m/s

• Acceleration = 22m/s²

• Time = 3s

According to first equation of motion

→ v = u + at

Where " v " is final velocity, " u " is initial velocity, " a " is acceleration and " t " is time.

• According to question

→ v = u + at

→ v = 4 + 22 × 3

→ v = 4 + 22 × 3

→ v = 4 + 66

→ v = 70 m/s

Hence,

• Final velocity is 70 m/s

More to know :-

• s = ut + ½ at² (second equation of motion)
• v² = u² + 2as (third equation of motion)
• Acceleration is the rate of change in velocity.
• Acceleration in negative is known as retardation

Answer 2

Answer :-

• Georgia is running 70m/s.

Given :-

• Georgia is jogging with a velocity of 4 m/sec when she accelerates at 22 m/s² for 3 seconds.

To Find :-

• How fast is Georgia running now ?

Solution :-

Here

• Initial velocity = 4m/s
• Acceleration = 22m/s²
• Time = 3s

From the first equation of motion,

→ v = u + at

Where

• v = final velocity
• u = initial velocity
• a = acceleration
• t = time

Put the values in the formula

According to question :-

v = u + at

→ v = 4 + 22 × 3

→ v = 4 + 66

→ v = 70m/s

Hence, the final velocity is 70m/s.