gerald has two sons, the age of the older son is 3 more than twice the age of the younger ,the product of their ages is 140 .how old is the younger son?
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Step-by-step explanation:
let age of younger son will be=X
older son will be=2(X+3)
product of their age is 140
(2x+6)*X=140
2x sqware+6x-140
divide by 2
X square+ 3x -70
factorisation method
X square+10x-7x-70
first 2 m s common
than last 2 m se common lege
X(X+10)-7(X+10)
X+10=0
X=-10
x-7=o
X=7
check
2(X+3)*X=140
2(7+3)*7= 140
hence proof
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