Gerald is one-fifth his father Ronald's age and Sue is one-seventh her mother Nancy's age. In 21
years, Gerald will be half his father's age and in 8 years, Sue will be a third the age of Nancy. How
many years younger or older than Gerald is Sue?
Answers
Given : Gerald is one-fifth his father Ronald's age and Sue is one-seventh her mother Nancy's age. In 21
years, Gerald will be half his father's age and in 8 years, Sue will be a third the age of Nancy.
Step-by-step explanation:
Father Age (Ronald) = 5F
Gerald is one-fifth his father Ronald's age = F
Mother Age (Nancy ) = 7S
Sue is one-seventh her mother Nancy's age = D
In 21 years, Gerald will be half his father's age
=> F + 21 = (1/2) (5F + 21)
=> 2F + 42 = 5F + 21
=> 3F = 21
=> F = 7
in 8 years, Sue will be a third the age of Nancy
=> S + 8 = (1/3)(7S + 8)
=> 3S + 24 = 7S + 8
=> 4S = 16
=> S = 4
Gerald Age = 7 Years
Sue Age = 4 Years
Sue is 3 year younger than Gerald
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