Get 50 POINTS by answering this question!1. Kamal bought 5 apples and 10 bananas at Rs 360.
the apple at a profit of 25% and banana at a
loss of 5%. If his overall profit was Rs 54.Find
cp of a apple and a banana.
Answers
Step-by-step explanation:
9 bananas at 4
cost per banana = 4/9
sold at 7/dozen
sp per unit = 7/12
profit % = (SP - CP)/CP × 100
= ( 7/12 - 4/9 )/4/9 × 100
= 31.25 %
According to the problem,
5x + 10y = 360
x + 2y = 72 ........(1)
Apple is sold at a gain of 25%
We have selling price = \frac{100+gainpercentage}{100} cp
100
100+gainpercentage
cp
s.p of apple = \frac{125}{100}x
100
125
x
Banana is sold at a loss of 5%
s.p of banana = \frac{100-loss percentage}{100}cp
100
100−losspercentage
cp
s.p of banana = \frac{95}{100}y
100
95
y
His profit is Rs 54
Total sale price = 360 + 54
= 414
414 = \frac{125}{100}x
100
125
x + \frac{95}{100}y
100
95
y
41400 = 125x + 95y
8280 = 25x + 19y.........(2)
(1)×25 ⇒ 25x + 50y = 1800..........(3)
Solving equations (2) and (3)
31y = -6480
But cost price can never be negative
Hence the condition in the question cannot be satisfied