Question

Get me physics formulas to calculate velocity and distamce with Derivation graph​

Answer 1

Explanation:

☞︎︎︎ Derivation

$\:$

Velocity time relation

$\:$

$\large \rm \mapsto \: \: a = \dfrac{v - u}{t}$

$\:$

$\large \rm \mapsto \: \: v - u = at$

$\:$

$\large \boxed{ \rm \mapsto \: \: v = u + at}$

$\:$

Position time relation

$\:$

AOCB =

$\large \rm \: = sum \: of \: parallel \: sides \times \dfrac{1}{2} h$

$\:$

$\large \rm \implies \: s = (ao + bc) \dfrac{1}{2 } \times ad$

$\:$

$\large \rm \implies \: s = (u + v) \times \dfrac{1}{2 } \times t$

$\:$

v = u + ar

$\:$

$\large \rm \implies \: s = (u + u + at) \dfrac{1}{2 } t$

$\:$

$\large \rm \implies \: s = (2u+ at) \dfrac{1}{2 } t$

$\:$

$\large \rm \therefore \boxed{\: \rm \: s = ut + \dfrac{at ^{2} }{2 } }$

Answer 2

Explanation:

☞︎︎︎ Derivation

$\:$

Velocity time relation

$\:$

$\large \rm \mapsto \: \: a = \dfrac{v - u}{t}$

$\:$

$\large \rm \mapsto \: \: v - u = at$

$\:$

$\large \boxed{ \rm \mapsto \: \: v = u + at}$

$\:$

Position time relation

$\:$

AOCB =

$\large \rm \: = sum \: of \: parallel \: sides \times \dfrac{1}{2} h$

$\:$

$\large \rm \implies \: s = (ao + bc) \dfrac{1}{2 } \times ad$

$\:$

$\large \rm \implies \: s = (u + v) \times \dfrac{1}{2 } \times t$

$\:$

v = u + ar

$\:$

$\large \rm \implies \: s = (u + u + at) \dfrac{1}{2 } t$

$\:$

$\large \rm \implies \: s = (2u+ at) \dfrac{1}{2 } t$

$\:$

$\large \rm \therefore \boxed{\: \rm \: s = ut + \dfrac{at ^{2} }{2 } }$