Get the solution .. in a morning walk 3 persons step off together and their steps measure 40,42,45 cm . what is the minimum distance each should walk so that each cover the same distance in complete steps
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That means we have to find out the lowest common multiple of 40,42 and 45
40= 2*2*2*5
42= 2*3*7
45= 3*3*5
So LCM = 2*2*2*3*3*5*7 = 2520
That means they have to walk for 2520 cm = 25.20 m to cover same distance.
40= 2*2*2*5
42= 2*3*7
45= 3*3*5
So LCM = 2*2*2*3*3*5*7 = 2520
That means they have to walk for 2520 cm = 25.20 m to cover same distance.
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