Question

Getting 10/9 with remainder theorem...is it correct?​

Answer 1

Answer:

10/9 is remainder

Step-by-step explanation:

given = 3y-1 to be divisible by 3ycube + 6ysqure+7y-2

so 3y-1=0 3y=1 y=1/3

substituting this in equations

3(1/3)3+6(1/3)3+7(1/3)-2

3(1/27)+6(1/9)+7(1/3)-2

3/27+6/9+7/3-2/1

cancel out

1/9+1/9+7/3-2/1

(take 1 cm as 9)

1/9+6/9+21/9-18/9

1+6+21-18/9=10/9 not equal to zero

hence y=1/3 is not a factor and remainder is 10/9