getting a number that is odd of probability witha all 6 steps
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Assuming the die to be unbiased, the probability distribution of X: the number obtained on tossing is
P(x) = 1/6 , x = 1,23,4,5,6.
Hence probability of getting an odd number = p(1) + p(3) + p(5) = 3/6 = 1/2.
P(x) = 1/6 , x = 1,23,4,5,6.
Hence probability of getting an odd number = p(1) + p(3) + p(5) = 3/6 = 1/2.
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