Physics, asked by etikalashok1939, 10 months ago

Geyser is rated 1500 volt and 250v this geyser is connected to 250 mains calculate (1) current drawn (2)energy consumed in 50 hrs (3) cost of energy consumed at rs 2.20per kwh

Answers

Answered by Steph0303
12

Answer:

Correct Question:

Geyser is rated 1500 W and 250 V this geyser is connected to 250 mains calculate:

  • Current drawn.
  • Energy consumed in 50 hrs.
  • Cost of energy consumed at rs 2.20 per kWh.

Power = Voltage × Current

According to the question,

  • Power = 1500 W
  • Voltage = 250 V

⇒ 1500 W = 250 V × I

⇒ I = 1500 / 250 = 6 A

Therefore Current drawn is 6 A.

⇒ Energy = Power × Time

Energy = 1500 W × 50 = 75000 Wh or 75 kWh

Cost of energy = Rs. 2.20 / kWh

⇒ 75 kWh = 75 × 2.20 = Rs. 165

Answered by Amritanshukesari4u
5

\huge{\textbf{\underline{\green{Answer:-}}}}

(1). \boxed{ Current = 6 A}

(2). \boxed{Energy = 75 kWh}

(3). \boxed{Cost\: of\: Energy = Rs.165}

\huge{\textbf{\underline{\green{Step-by-Step Explanation:-}}}}

There is a mistake in the question. So, the correct question is here at the bottom.

Question: Geyser is rated 1500 watt and 250 volt. This geyser is connected to 250 mains. Calculate

(1) Current drawn

(2) Energy consumed in 50 hrs

(3) Cost of energy consumed at Rs. 2.20per kWh

Solution:-

Given,

Power, P = 1500 W

Potential Difference, V = 250 V

As we know that,

\boxed{P = V × I}

\boxed{.°.I = \frac{P}{V}}

where

I = Current

V = Potential Difference

P = Power

Now, putting the given values.

\implies{I = \frac{1500}{250}}

\implies{ I = 6 A}

\boxed{\bold{ .°. Current = 6 A}}

Now,

As we know that,

\boxed{E = P × t}

where

E = Energy

P = Power

t = time

\implies{E = 1500 × 50}

\implies{E = 75000 Wh}

\implies{E = 75 kWh}

\boxed{\bold{.°. Energy = 75 kWh}}

Now,

Cost of energy = Rs. 2.20 per kWh

\implies{Cost = 75 × 2.20}

\implies{Cost = Rs.165}

\boxed{\bold{.°.Cost\: of\: Energy = Rs.165}}

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