Math, asked by man8535, 5 hours ago

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Answered by duser3484
1

Answer:

 {2}^{ {x}^{2} }  =  {4}^{2(x - 1)}  \\ {2}^{  {x}^{2} }  =  {2}^{2(2x - 2)}  \\  {2}^{ {x}^{2} }  =  {2}^{4x - 4}  \\ on \: comparing \: the \: bases \: we \: get -  \\  {x}^{2}  = 4x - 4 \\ x²-4x + 4 = 0 \\ x²-(2  + 2)x + 4 = 0 \\ x²-2x - 2x + 4 = 0 \\ x(x - 2) - 2(x - 2) = 0 \\ (x - 2)(x - 2) = 0 \\ hence \: x = 2

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