Math, asked by mohdsayam798, 11 months ago

घ) यदि द्विघात बहुपद (a2 + a) x2 + 13x + 6a का एक शून्यक दूस
का व्युत्क्रम है तो a का मान ज्ञात कीजिए​

Answers

Answered by knjroopa
1

Step-by-step explanation:

Given If a zero of the quadratic polynomial (a2 + 9) x2 + 13x + 6a  is the inverse of other, then find the value of a

  • Let one zero of the quadratic polynomial be α
  • Therefore the other zero of the quadratic polynomial is 1/α
  • Product of zeroes = α x 1 / α = 1
  •            6a / a^2 + 9 = 1
  •      6a = a^2 + 9
  • So a^2 – 6a + 9 = 0
  • So a^2 – 3a – 3a + 9 = 0
  • So a(a – 3) – 3(a – 3) = 0
  • So (a – 3) = 0
  • Or a = 3

Therefore the value of a is 3

Reference link will be

https://brainly.in/question/193997

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