Question

Gibbs energy and equlibrium constant

Answer 1

Explanation:

In fact, under the conditions that a reaction is in a state of dynamic equilibrium, ΔG (as opposed to the free energy change under standard conditions, ΔG°) is zero. ... ln K (that is a letter L, not a letter I) is the natural logarithm of the equilibrium constant K.

Answer 2

The equation, ΔG = ΔG°+ RT ln Q, is derived on Wikipedia, under the subsection Thermodynamics. Remember, Q is the reaction quotient, which at equilibrium is equal to the equilibrium constant, K. ... Since, at equilibrum, ΔG = 0, the expression can be rearranged to the familiar ΔG°= -RT ln K.

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