Question

Gift Find the points on the curve 4x2 +9y2 = 1 where the tangents are perpendicular to the line
2y + x = 0​

Answer 1

Answer:

4x^2+9y^2=1

{2x+3y}^2=1

2x^2+3y^2+2.2x.3y=1

2x^2+3y^2+12xy=1

2y+x=0

2y= -x

y=-x÷2