Question

gimme ans of this question plss I will mark as brainliest ans of this question ​

Answer 1

Answer:

hiu

nsbdkdkfgkogg9g9snbdjdjfkc

Answer 2

Step-by-step explanation:

$\frac{ {2}^{x - 1} + {2}^{x} }{ {2}^{x + 1} - {2}^{x} } = \frac{3}{2} \\ \frac{ \frac{ {2}^{x} }{ {2}^{1} } + {2}^{x} }{ ({2}^{x} \times {2}^{1}) - {2}^{x} } = \frac{3}{2} \\ \frac{ \frac{ {2}^{x} +( {2}^{x} \times 2) }{2} }{( {2}^{x} \times 2) - {2}^{x} } = \frac{3}{2} \\ \frac{ {2}^{x} + ( {2}^{x} \times 2) }{(2 \times 2 \times {2}^{x}) - ( {2}^{x} \times 2) } = \frac{3}{2} \\ \frac{ {2}^{x} (1 + 2) }{ {2}^{x} (4 - 2)} = \frac{3}{2} \\ \frac{3 \times {2}^{x} }{2 \times {2}^{x} } = \frac{3}{2} \\ x = 0$

at x=0, 2^x=1

so lhs =rhs