Question

gipost chemical Analysis of a carbon
compound gave the following %
composition by the weights of the
presenf carbon 10-6°/ „Hydrogen
0.84% , chlorine 89.10 %.
elements​

Answer 1

Answer:

Element

      Moles

 Least ratio

C

     

12

54.55

​  

=4.54                  

   

2.27

4.54

​  

=2

H

     

1

9.09

​  

=9.09

   

2.27

9.09

​  

=4

O

     

16

36.36

​  

=2.27                  

2.27

2.27

​  

=1

From the above calculations, the empirical formula =C  

2

​  

H  

4

​  

O.

Empirical formula weight =12×2+1×4+16=44 g.

Vapour density (VD) =44 g.

Molecular weight =2×VD=2×44=88 g.

n=  

Empirical formula weight

Molecular weight

​  

=  

44

88

​  

=2

Molecular Formula =2× Empirical formula=2×(C  

2

​  

H  

4

​  

O)=C  

4

​  

H  

8

​  

O  

2

​  

.