Giri does 2/5 piece of work in 10 days. Ankit does 5/9 of the remaining work in 15 days and Gaurav finishes remaining work in
x days. If they can do whole work in 450/43
days working together, then find the value of x?
Answers
Given :- Giri does 2/5 piece of work in 10 days. Ankit does 5/9 of the remaining work in 15 days and Gaurav finishes remaining work in x days. If they can do whole work in 450/43 days working together, then find the value of x?
Solution :-
Given that,
→ Giri does 2/5 piece of work in = 10 days.
So,
→ Giri does 1 piece of work in = 10 * (5/2) = 25 days.
Now,
→ Left work to be done = 1 - (2/5) = (3/5)
given that,
→ Ankit does 5/9 of the remaining work in = 15 days.
→ (5/9) of (3/5) work in = 15 days..
→ (1/3) work in = 15 days.
→ 1 piece of work in = 45 days.
Now,
→ Left work to be done = (3/5) - (1/3) = (9 - 5)/15 = (4/15) units.
and, Gaurav finishes remaining work in x days.
So,
→ gaurav do (4/15) piece of work in = x days.
Than,
→ gaurav do 1 piece of work in = (15x/4) days..
Now, we have given that, they can do whole work in 450/43 days working together .
Therefore ,
→ Per day work of all three = (43/450)
→ giri per day work + ankit per day work + gaurav per day work = (43/450)
→ (1/25) + (1/45) + (4/15x) = (43/450)
→ (9x + 5x + 60) /225x = 43/450
→ 2(14x + 60) = 43x
→ 28x + 60 = 43x
→ 43x - 28x = 60
→ 15x = 60
dividing both sides by 15,
→ x = 4. (Ans.)
Hence, the value of x is 4.
{ Excellent question. }
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Answer:
previous and was mistake from here
2(14x+60)=43x
28x+120=43x
120=15x
x=8days