girl having mass of 35 kg sits on a trolley of mass 5 kg is Lord he is given initial velocity of 4 metre per second by applying a force in trolley comes to rest after travelling a distance of 16 m how much work is done on the trolley
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Work done on trolley = Change in kinetic energy
= 0.5 m(v² - u²)
= 0.5 × 35 kg × [(0 m/s)² - (4 m/s)²]
= -280 Joule
∴ 280 J of work is done on trolley.
= 0.5 m(v² - u²)
= 0.5 × 35 kg × [(0 m/s)² - (4 m/s)²]
= -280 Joule
∴ 280 J of work is done on trolley.
Answered by
1
Work done = Kinetic Energy Change
= 0.5 m(v² - u²)
= 0.5 × 35 kg × [(0 m/s)² - (4 m/s)²]
= 280 Joule
∴ 280 J of work is done on trolley.
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