girl of mass 30 kg is running along a circular path of radius 2 m with uniform speed how much work is done by the girl?(g=9.8m/s square
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Answer:
Let the coefficient of friction be μ.
The centrifugal force will balance the friction force so that the car does not slip.
∴
r
mv
2
=μmg ⟹ μ=
rg
v
2
μ=
20×9.8
(12.5)
2
=0.8
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