Question

girls_join_fast_jcu-oihg-tqb​

Answer 1

Answer:

no_we are no there

Explanation:

Given polynomial equation x2+x-p (p+1)

x2+x-p(p+1)=0

On factorising we get,

x2+(p+1)x-px-p(p+1)=0

x(x+p+1) -p(x+p+1)=0

(x+p+1)(x-p)=0

x=-p-1, and x= p

The zeros of polynomial are: p-1 and p