Question

Gita's purse had 78-2 rupee coins ,102-5 rupee coins and 111-10 rupee coins.how many compartments did she need at minimum to hold all thje coins in such a way that every compartment has same number of coins in the same category

Answer 1

Answer:

Step-by-step explanation:

Let the no. Of 25p coins be x and 50p coins 40-x

Value of 25p coins = 25x

Value of 50p coins = 50(40-x)

=2000-50x

Now,

According to question

25x + 2000-50x = 12.50 * 100

-30x =1250-2000

-30x= -750

30x=750

X = 750/30

X= 25

Now no. Of 25p coins= 25

No. Of 50p coins= 40-25

= 15

Answer 2

Answer:

Total no.of compartments required = 97

Step-by-step explanation:

Prime factorizing 78, 102 , 111, we get

78= 2*3*13

102= 2*3*17

111= 3*37

Therefore, HCF = 3

So, total no.of coins in one compartment will be 3

Now,

Total no.of compartments = (78+102+111)/3    [3 is no.of coins in 1 compartment]

                                           =97

So total no.of compartments required is 97