Gita's purse had 78-2 rupee coins ,102-5 rupee coins and 111-10 rupee coins.how many compartments did she need at minimum to hold all thje coins in such a way that every compartment has same number of coins in the same category
Answers
Answered by
5
Answer:
Step-by-step explanation:
Let the no. Of 25p coins be x and 50p coins 40-x
Value of 25p coins = 25x
Value of 50p coins = 50(40-x)
=2000-50x
Now,
According to question
25x + 2000-50x = 12.50 * 100
-30x =1250-2000
-30x= -750
30x=750
X = 750/30
X= 25
Now no. Of 25p coins= 25
No. Of 50p coins= 40-25
= 15
Answered by
11
Answer:
Total no.of compartments required = 97
Step-by-step explanation:
Prime factorizing 78, 102 , 111, we get
78= 2*3*13
102= 2*3*17
111= 3*37
Therefore, HCF = 3
So, total no.of coins in one compartment will be 3
Now,
Total no.of compartments = (78+102+111)/3 [3 is no.of coins in 1 compartment]
=97
So total no.of compartments required is 97
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