Question

Gitu travels 300 Km to her home partly by train and partly
by bus. She takes 4 hours if she travels 60 km by train
and the remaining by bus. If she travels 100 km by train
and the remaining by bus, she takes 10 miniutes longer.
Find the speed of train and the bus
separately
​

Answer 1

Answer:

We need to apply the formula of speed

Step-by-step explanation:

In Train = 60 km -4 hours

In Bus = 200 km - 10 minutes

1 hour = 15 km By train

10 minutes = 200 km By bus

Find the speed of the train when it travels 100 km and bus when it travels 200 km .

Speed = Distance/Time

so we will find our answer

it would be  3000 and 20

Answer 2

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Let the speed of train and bus be u km/h and v km/h respectively.

According to the question,

$\frac{60}{u} + \frac{240}{v} = 4$....(i)

$\frac{100}{u} + \frac{200}{v} = 4 + \frac{10}{60} = \frac{25}{6}$....(ii)

Let $\frac{1}{u} = p\: and \frac{1}{v} = q$

The given equations reduce to:

60p + 240q = 4 ....(iii)

100p + 200q = $\frac{25}{6}$

600p + 1200q = 25....(iv)

Multiplying equation (iii) by 10, we obtain:

600p + 2400q = 40....(v)

Subtracting equation (iv) from equation (v), we obtain:

1200q = 15

q = $\frac{15}{1200} = \frac{1}{80}$

Substituting the value of q in equation (iii), we obtain:

60p + 3 = 4

60p = 1

p = $\frac{1}{60}$

:. p = $\frac{1}{u} = \frac{1}{60}$, q = $\frac{1}{v} = \frac{1}{80}$

u = 60 km/h , v = 80 km/h

Thus, the speed of train and the speed of bus are 60 km/h and 80 km/h respectively.

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