Question

Give a brief note on "Escape Velocity".

Answer 1

Answer:

escape velocity is the minimum speed needed for an object to escape from the gravitational influence of a massive body. The escape velocity from Earth is about 11.186 km/s (6.951 mi/s; 40,270 km/h; 25,020 mph)[1] at the surface

Explanation:

Answer 2

Escape Velocity:

• It's the minimum velocity required for an object (located at any planet's surface) to just escape the planet's gravitational field.

• When the projectile escapes to infinity, it has no Kinetic energy nor it has potential energy.

• $\red{\boxed{\bold{V_{e} = \sqrt{ \dfrac{2GM}{r} }}}}$

• Ve is also given as $\red{\bold{\boxed{V_{e}= \sqrt{ \dfrac{2GM}{R + h} }}}}$

Where r = R + h (r = Distance from centre of planet and h = Height above surface of planet)

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Escape Velocity depends on:

• Mass of the planet (M).

• Radius of the planet (R).

• Position from where the particle is projected.

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Escape Velocity doesn't depend on:

• Mass of the body which is projected.

• Angle of protection.

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Knowledge cell :-

• Escape Velocity at Earth's surface : 11.2 km/s

• Escape Velocity at Moon: 2.31 km/s

• There's no atmosphere at Moon as there root mean square velocity is more than escape velocity.