give a neutral element isoelectronic with CH3+
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HF....
F has 7 electrons and H has 1 Electron
So 7+1=8
Here in CH3+
There are 6 Electron for C and 3 electrons for H
So 6+3=9
But there is a positive charge means loss of an electron
So 9-1=8
F has 7 electrons and H has 1 Electron
So 7+1=8
Here in CH3+
There are 6 Electron for C and 3 electrons for H
So 6+3=9
But there is a positive charge means loss of an electron
So 9-1=8
nikhil365825:
how??
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