Question

Give a proof by contradiction of the theorem “If 3n+2 is odd, then n is odd.”​

Answer 1

Answer:

Proof: Assume 3n+2 is odd and n is even. Since n is even, then n=2k for some integer k. It follows that 3n+2 = 6k+2 = 2(3k+1). Thus, 3n+2 is even

Answer 2

Answer:

Theorem (For all integers n) If 3n " 2 is odd, then n is odd. ... Thus 3n " 2 is even, because it equals 2F for integer F # 3k " 1. So 3n " 2 is not odd. :e have shown that , n is odd! % , 3n " 2 is odd!, thus its contra%positive 3n " 2 is odd!

Step-by-step explanation:

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