Question

Give a reason why does the pendulum clock become faster at the equator?
mention the relation between the time period of simple pendulum and the acceleration due to gravity with mathmatical expression?

Answer 1

Answer 1

Since, a pendulum gives a right time at the equator but when it is taken to any pole then it become fast it is due to reason that the acceleration due to gravity of pole is greater than acceleration due to gravity at equator due to which time period decreases and the clock become fast.

Answer 2

Vinod and time period of simple pendulum is given as

$t = 2\pi \sqrt{ \frac{l}{g} }$

So from above formula

time period of simple pendulum is inversely proportional to square root of gravity .

Which means as action due to gravity decreases at height and depth time period increases also during free fall when is equals to zero then time become infinite.

:-)

Answer 2

Answer:

Explanation:

HERE IS YOUR ANSWER..

➡️It becomes faster because of the strength of Earth's gravitational field is not uniform everywhere, a given pendulum swings faster, and thus has a shorter period, at low altitudes and at Earth's poles than it does at high altitudes and at the Equator.

➡️RELATION OF TIME PERIOD WITH RESPECT TO ACCELERATION DUE TO GRAVITY..

The time period of a simple pendulum depends on the

➡️length of the pendulum (l)

➡️the acceleration due to gravity (g), which is expressed by the relation,

➡️For small amplitude of oscillations. If we know the value of l and T, we can calculate the acceleration due to gravity, g

➡️The time period of a body (simple pendulum of length L) which is executing SHO under the influence of gravity of earth is given by the standard relation..

➡️MATHEMATICAL EXPRESSION..

➡️T=2π (L/g)^1/2 (Say as T equals 2pi into root of L by g)

➡️Where g= acceleration due to gravity and L is length of the simple pendulum..

HOPE IT HELPS...

BRAINLIEST PLEASE..❤☺