Question

Give a relation between the electric field and intensity.



My percentage is 89 in 11th and urs​

Answer 1

Answer:

The relation is very simple. Electric field intensity is equal to the negative of rate of change of potential with respet to the distance or it can be defined as the negative of the rate of derivative of potential difference, V with respect to r, E = - dV/dr.

Answer 2

Answer:

Consider the an electric dipole of charges +q and −q separated by distance 2a with center at O.

Goal: To find electric field at point P on the axial line of the dipole, OP=r.

Let E

1

and E

2

be electric field on P due to charges +q and −q respectively.

E

1

=

(r−a)

2

kq

along AP

E

2

=

(r+a)

2

kq

along BP

The resultant electric field at P, E=E

1

−E

2

(as both E

1

and E

2

are in opposite direction)

E=

(r−a)

2

kq

−

(r+a)

2

kq

=kq

(r

2

−a

2

)

2

4ra

Define, p=2aq

E=k

(r

2

−a

2

)

2

2pr

If r>>a, then E=k

r

4

2pr

=k

r

3

2p

.

In vector form,

E

=k

r

3

2

p

.