Question

Give a solution of (1-t^2)x-2tx+6x=0​

Answer 1

Answer:

x-t²x-2tx+6x=0

-t²x-2tx+7x=0

t²x+2tx-7x=0

x(t²+2t-7)=0

either x=0 or t²+2t-7=0

now t²+2 t-7=0