Question

➡Give all identities ( formula ) of Algebra

( with also expansion )

⭕Content Quality Answer Required

❎ No Spamming ❎

Answer 1

Hey mate!

Here is yr answer.....


Identities of Algerbra :
~~~~~~~~~~~~~~~~~~~

(a+b)² = a²+2ab+b²

(a-b)² = a² -2ab +b²

(a+b)(a-b) = a²-b²

(a-b)² +2ab = a²+b²

(a+b+c)² = a²+b²+c²+2ab+2bc+2ca

(x+a)(x+b) = x²+(a+b)x+ab

(a+b)³ = a³+3a²b +3ab²+b³

(a-b)³ = a³-3a²b+3ab²-b³

a³+ b³+c³ -3abc = (a+b+c)(a²+b²+c²-ab-bc-ca)

a³+b³ = (a+b)(a²-ab+b²)

a³-b³ = (a-b) (a²+ab+b²)



Hope it helps u...


#BeBrainly

Answer 2

Hey buddy!

Here is yr answer.......


Algebra :
~~~~~~~

<> it is a part or branch of mathematics in which ----

=> Numbers are represented by letters / symbols

=> Quantities are represented by equations / identities/ Formulae

The identities of algebra are :
_______________________


=> (a+b)² = a²+2ab+b²

=>a+b)(a+b) = a²+2ab+b²

=>a²+ab+b²+ab = a²+2ab+b²

=>a²+2ab+b² = a²+2ab+b²
_________________________


=> (a-b)² = a²-2ab+b²

=> a-b) (a-b) = a²-2ab+b²

=> a²-ab+b²-ab = a²-2ab+b²

=> a²-2ab+b² = a²-2ab+b²

_________________________

=> a²-b² = (a+b)(a-b)

=> a²-b² = a(a-b) +b(a-b)

=> a²-b² = a²-ab+ab-b²

=> a²-b² = a²-b²

_________________________

=> a²+b² = (a-b)² +2ab

=> a²+b² = a²-2ab+b² +2ab

=> a²+b² = a²+b²

_____________________________

=> (a+b+c)² = a²+b²+c²+2ab+2bc+2ca

=> (a+b+c)(a+b+c)=a²+b²+c2+2ab+2bc+2ca

=> a²+ab+ac+ab+b²+bc+ac+bc+c² = a²+b²+c2+2ab+2bc+2ca

=> a²+b²+c2+2ab+2bc+2ca = a²+b²+c2+2ab+2bc+2ca


_____________________________

=> (x+a)(x+b) = x²+(a+b)x + ab

=> x(x+b)+a(x+b) = x²+(a+b)x + ab

=> x²+bx+ac+ab = x²+(a+b)x + ab

=> x²+(a+b)x + ab = x²+(a+b)x + ab

_____________________________


=> (a+b)³ = a³+b³+3ab(a+b)

=> (a+b)(a+b)(a+b) = a³+b³+3ab(a+b)

=> a³+b³+3ab(a+b) = a³+b³+3ab(a+b)

_____________________________

=> (a-b)³ = a³+b3+3ab(-a+b)

=> (a-b)(a-b)(a-b) = a³+b3+3ab(-a+b)

=> a³+b3+3ab(-a+b) = a³+b3+3ab(-a+b)

______________________________

=> a³+b³+c³ -3abc = (a+b+c)(a2+b²+c²-ab-bc-ca)

=> a(a²+b²+c²-ab-bc-ca) + b(a²+b²+c²-ab-bc-ca)+c(a²+b²+c²-ab-bc-ca) = (a+b+c)(a2+b²+c²-ab-bc-ca)

=> (a+b+c)(a2+b²+c²-ab-bc-ca) = (a+b+c)(a2+b²+c²-ab-bc-ca)

______________________________

=> a³+b³ = (a+b)(a²-ab+b²)

=> a(a²-ab+b²) + b(a²-ab+b²) = (a+b)(a²-ab+b²)

=> (a+b)(a²-ab+b²) = (a+b)(a²-ab+b²)

______________________________


=> a³ -b³ = (a-b) (a²+ab +b²)

=> a(a²+ab+b²)-b(a²+ab+b²) = (a-b) (a²+ab +b²)

=> (a-b) (a²+ab +b²) = (a-b) (a²+ab +b²)

_____________________________




Hope it helps....


@Destroyer

#Be Brainly