Math, asked by ravi2065, 11 months ago

give all polynomials formula​

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Answered by legend72
0

Answer:

here u got your answer.

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Answered by Mavneetkaur18
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polynomial identities(short multiplication formulas):

(x + y)2 = x2 + 2xy + y2

(x - y)2 = x2 - 2xy + y2

Example 1:

....If x = 10, y = 5a

(10 + 5a)2 = 102 + 2·10·5a + (5a)2 = 100 + 100a + 25a2

-x + y)2 = (y - x)2 = y2 - 2xy + x2

(-x - y)2 = (-(x + y))2 = (x + y)2 = x2 + 2xy + y2

Formulas for 3rd degree:

(x + y)3 = x3 + 3x2y + 3xy2 + y3

(x - y)3 = x3 - 3x2y + 3xy2 - y3

Example: (1 + a2)3 = 13 + 3.12.a2 + 3.1.(a2)2 + (a2)3 = 1 + 3a2 + 3a4 + a6

(x + y + z)2 = x2 + y2 + z2 + 2xy + 2xz + 2yz

(x - y - z)2 = x2 + y2 + z2 - 2xy - 2xz + 2yz

Factor Rules

x2 - y2 = (x - y)(x + y)

x2 + y2 = (x + y)2 - 2xy

or

x2 + y2 = (x - y)2 + 2xy

Example: 9a2 - 25b2 = (3a)2 - (5b)2 = (3a - 5b)(3a + 5b)

x3 - y3 = (x - y)(x2 + xy + y2)

x3 + y3 = (x + y)(x2 - xy + y2)

If n is a natural number

xn - yn = (x - y)(xn-1 + xn-2y +...+ yn-2x + yn-1)

If n is even (n = 2k)

xn + yn = (x + y)(xn-1 - xn-2y +...+ yn-2x - yn-1)

If n is odd (n = 2k + 1)

xn + yn = (x + y)(xn-1 - xn-2y +...- yn-2x + yn-1)

More Algebraic Formulas

2(a2 + b2) = (a + b)2 + (a - b)2

(a + b)2 - (a - b)2 = 4ab

(a - b)2 = (a + b)2 - 4ab

a4 + b4 = (a + b)(a - b)[(a + b)2 - 2ab]

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