Give all the formula of trigonometry with use of examples.
Answers
Answer:
ᴛʜᴇ ʀᴇᴄɪᴘʀᴏᴄᴀʟ ɪᴅᴇɴᴛɪᴛɪᴇs ᴀʀᴇ ɢɪᴠᴇɴ ᴀs :
cosec θ = 1/sin θ
sec θ = 1/cos θ
cot θ = 1/tan θ
sin θ = 1/cosec
cos θ = 1/sec θ
tan θ = 1/cot θ
Step-by-step explanation:
◦•●◉✿ ✿◉●•◦
ʜɪɪ! ᴄᴀɴ ʏᴏᴜ ʙᴇ ᴍʏ ғʀɪᴇɴᴅ
Answer:
Trigonometric Identities are the equalities that involve trigonometry functions and holds true for all the values of variables given in the equation.
There are various distinct trigonometric identities involving the side length as well as the angle of a triangle. The trigonometric identities hold true only for the right-angle triangle.
All the trigonometric identities are based on the six trigonometric ratios. They are sine, cosine, tangent, cosecant, secant, and cotangent. All these trigonometric ratios are defined using the sides of the right triangle, such as an adjacent side, opposite side, and hypotenuse side. All the fundamental trigonometric identities are derived from the six trigonometric ratios.
Sin θ = 1/Csc θ or Csc θ = 1/Sin θ
Cos θ = 1/Sec θ or Sec θ = 1/Cos θ
Tan θ = 1/Cot θ or Cot θ = 1/Tan θ
sin2 a + cos2 a = 1
1+tan2 a = sec2 a
cosec2 a = 1 + cot2 a
Tan θ = Sin θ/Cos θ
Cot θ = Cos θ/Sin θ
Sin (-θ) = – Sin θ
Cos (-θ) = Cos θ
Tan (-θ) = – Tan θ
Cot (-θ) = – Cot θ
Sec (-θ) = Sec θ
Csc (-θ) = -Csc θ
Sin (90 – θ) = Cos θ
Cos (90 – θ) = Sin θ
Tan (90 – θ) = Cot θ
Cot ( 90 – θ) = Tan θ
Sec (90 – θ) = Csc θ
Csc (90 – θ) = Sec θ
Step-by-step explanation: