give an balanced equation :Lead nitrate solution reacts with sodium hydroxide first little
and then in excess.
Answers
Answered by
22
Answer:
Pb(NO3)2 + 2NaOH → Pb(OH)2 + 2NaNO. Lead(II) nitrate react with sodium hydroxide to produce lead(II) hydroxide and sodium nitrate.
Addition of sodium hydroxide to lead nitrate solution initially gives white precipitate which solublizes in excess of NaOH added.
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Answered by
8
Answer:
The answer given above is surely wrong......
The correct answer will be......
Pb(NO3)2+2NaOH(in excess) ---->Pb(OH)2+2NaNO3
Explanation:
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