Physics, asked by pramod123sunny, 1 year ago

Give an brief explanation on
photoelectric effect?

Answers

Answered by sona561
1
The photoelectric effect refers to the emission, or ejection, of electrons from the surface of, generally, a metal in response to incident light. 

Energy contained within the incident light is absorbed by electrons within the metal, giving the electrons sufficient energy to be 'knocked' out of, that is, emitted from, the surface of the metal. 

Using the classical Maxwell wave theory of light, the more intense the incident light the greater the energy with which the electrons should be ejected from the metal. That is, the average energy carried by an ejected (photoelectric) electron should increase with the intensity of the incident light. 

In fact, L�nard found that this was not so. Rather, he found the energies of the emitted electrons to beindependent of the intensity of the incident radiation.
Answered by Saba05
1
The Photo electric effect refers to the emission, or ejection, of electrons from the surface of, generally, a metal in response to incident light.
According to classical electromagnetic theory, this effect can be attributed to the transfer of energy from the light to an electron. From this perspective, an alteration in the intensity of light would induce changes in the kinetic energy of the electrons emitted from the metal. Furthermore, according to this theory, a sufficiently dim light would be expected to show a time lag between the initial shining of its light and the subsequent emission of an electron. 
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