Question

give an example each of two different in rational number those 1 sum is an irrational number to product is an irrational number​

Answer 1

Step-by-step explanation:

Formula used: (a+b)(a−b)=a2−b2

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Related Questions

1. Give an example of 2 irrational numbers whose sum is rational.

2. Give an example of 2 irrational numbers whose product is rational.

Answer

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Hint: We will think of any 2 irrational numbers, we will find their sum and see if it is a rational number. We will think of any 2 irrational numbers, we will find their product and see if it is a rational number.

Formula used: (a+b)(a−b)=a2−b2

Complete step-by-step answer:

We will look at some properties of rational and irrational numbers that will help us in solving the question:

We know that a number is a rational number if it can be expressed in the form pq

where p

and q

are integers with no common factor and q≠0

.

We know that a number is an irrational number if it cannot be expressed in the form pq

where p

and q

are integers with no common factor and q≠0

.

We know that the sum of a rational and an irrational number is always an irrational number.

We know that the difference of a rational and an irrational number is always an irrational number.

We know that 7–√

is an irrational number.

We can conclude from the 3rd property that 2+7–√

is an irrational number.

We can conclude from the 4th property that 2−7–√

is an irrational number.

We will take the first number as 2+7–√

and the second number as 2−7–√

.

We will find the sum of the 2 numbers:

(2+7–√+(2−7–√

=2+7–√+2−7–√

=2+2+7–√−7–√

= 4

4 is a rational number.

We will find the product of the 2 numbers. We will substitute 2 for a

and 7–√

for b

in the formula:

(2+7–√).(2−7–√)

=22−(7–√

= 4 - 7

hope it's helpful dear mark as brainliest plss

= - 3

−3

is a rational number.

∴2+7–√

and 2−7–√

are 2 irrational numbers whose sum as well as the product are rational numbers.