Question

Give an example of molecule in which the empirical formula is $CH_{2}O$ and the ratio of molecular formula weight and empirical formula weight is 6.

Answer 1

"Empirical formula and the molecular formula are mathematically related as  

Molecular formula =$n \times$ empirical formula

Example of a molecule whose "empirical formula" is${ H }_{ 2 }O$:

The "empirical formula" for Glucose $C_{ 6 }H_{ 12 }O_{6} \quad is\quad CH_{ 2 }O$

The molecular formula for glucose is $C_{ 6 }H_{ 12 }O_{ 6 }$

The molecular formula of glucose $C_{ 6 }H_{ 12 }O_{ 6 }\quad =\quad 6\quad \times \quad CH_{ 2 }O$(Since by the formula)

The molecular weight of glucose is $180 g/mol = 6 \times 30 g/mol$

Thus, the ratio of molecular formula weight and empirical formula weight is 6."

Answer 2

Empirical formula and the molecular formula are mathematically related as  

Molecular formula =n \timesn× empirical formula


Example of a molecule whose "empirical formula" is{ H }_{ 2 }OH2​O :


The "empirical formula" for Glucose C_{ 6 }H_{ 12 }O_{6} \quad is\quad CH_{ 2 }OC6​H12​O6​isCH2​O

The molecular formula for glucose is C_{ 6 }H_{ 12 }O_{ 6 }C6​H12​O6​

The molecular formula of glucose C_{ 6 }H_{ 12 }O_{ 6 }\quad =\quad 6\quad \times \quad CH_{ 2 }OC6​H12​O6​=6×CH2​O(Since by the formula)


The molecular weight of glucose is 180 g/mol = 6 \times 30 g/mol180g/mol=6×30g/mol

Thus, the ratio of molecular formula weight and empirical formula weight is 6."