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9. A battery of 9 V is connected in series with resistors of 0.2 ohm 0.3 ohm 0.4 ohm 0.5 ohm and 12 ohm respectively. How much current would flow through the 12 ohm resistor?
10. How many 176 ohm resistors (in parallel) are required to carry 5 A on a 220 V line?
mannu2001:
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Solution :-
9)
R eq= R1+R2+R3+R4
=13.4 ohm
Now,
V=ir
i=9/13.4
i=0.67 A
When resistors are connected in series, current is same in all the resistors. Hence, current in 12 ohm resistor =0.67 Ampere.
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