Question

give Ans of part 2nd . please dont spam​

Answer 1

Answer:

Hey mate...

here is your answer :-

Step-by-step explanation:

(ii) In ΔAOB & ΔAOC,

AB = AC (Given)

∠OBA= ∠OCA (from eq1)

OB = OC. (from eq 2)

Therefore, ΔAOB ≅ ΔAOC

( by SAS congruence rule)

Then,

∠BAO = ∠CAO

(by CPCT)

So, AO is the bisector of ∠BAC.

Hope it helps you...!!!!

Mark as brainliest :)

Answer 2

$\it\huge\mathfrak\red{Answer}$]

In ΔAOB & ΔAOC,

AB = AC (Given)

∠OBA= ∠OCA (from eq1)

OB = OC. (from eq 2)

Therefore, ΔAOB ≅ ΔAOC

( by SAS congruence rule)

Then,

∠BAO = ∠CAO

(by CPCT)

So, AO is the bisector of ∠BAC.