Question

✈Give ans with Solution.(25+Points)
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Answer 1

Explanation:

from left to right let figures be I, II , III , V

and let triangle above III be IV

total distance = area under graph

= I+II+III + IV + V

area of I = (1/2) × 10 × 20

= 100m²

Area of II = 10 × 20

= 200m²

area of III = 5× 20

= 100 m²

area of IV = (1/2) × 10 × 5

=25m²

area of V=( 1/2) × 10 ×30

= 150m²

total area = 150+25+100+200+100

= 575m²

Answer 2

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