Question

give answer correctly....with formulas and explanation....best ans..will be marked as brainiliest
....​

Answer 1

Given:

coin is tossed three times.

To find:

Getting head on middle coin = ?

Getting exactly one tail

Getting no tail.

Solution:

In tossing three coins, the sample space is given by

S = {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT}

And, therefore, n(S) = 8.

(i)

Let A be the event of getting head on middle coin.

A = {THT, HHH, HHT, THH}

n(A) = 4

∴ P(A) = n(A)/n(S) = 4/8 = 1/2

(ii)

Let B be the event of getting exactly one tail.

B = {HHT, HTH,THH}

n(B) = 3

∴ P(B) = n(B)/n(S) = 3/8

(iii)

Let E be the event of getting no tail.

E = {HHH}

n(E) = 1

∴ P(E) = 1/8

Result:

(i) 1/2

(ii) 3/8

(iii) 1/8

#BeBrainly

Answer 2

Answer:

SAMPLE SPACE (S)={H,H,H,T,T,T}

n(S)=6

i)LET A BE THE EVENT OF GEETING A HEAD ON MIDDLE COIN.

A={H}

AS IT HAS BEEN SAID ON THE MIDDLE COIN SO SAMPLE SPACE FOR THIS ONE WILL BE TWO BECAUSE MIDLLE COIN BASICALLY MEANS 1 COIN.

n(A)=1

n(S^2)=2 (SPECIAL CASE FOR THIS)

P(A)=n(A)/n(S^2)=1/2

ii)LET B BE THE EVENT OF GETTING EXACTLY 1 TAIL.

B={T}

n(B)=1

P(B)=n(B)/n(S)

=1/6

iii)LET C BE THE EVENT OF GETTING NO TAIL

C={H,H,H}

n(C)=3

P(C)=n(C)/n(S)

=3/6

=1/2

ANS》

1. 1/2
2. 1/6
3. 1/2

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