Question

give answer. ...........
factorised it​

Answer 1

$\huge\underline\bold\purple{ANSWER :}$

➡ 3x² - 2√6x + 2 = 0

➡ 3x² - √6x - √6x + 2 = 0

➡ 3x² - (√2)(√3x) - (√2)(√3x) + 2 = 0

➡ √3x(√3x - √2) - √2(√3x - √2) = 0

➡ (√3x −√2) (√3x −√2) = 0

➡ √3x - √2 = 0 ; √3x - √2 = 0

➡ x = √2/3 ; x = √2/3

$\boxed{∴ roots\;are = √2/3 }$

Step-by-step explanation:

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Answer 2

Answer:

I hope you understand...