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A train covered a distance at uniform speed. If the train is 10km/h faster, it would take 2 hours less than the scheduled time. And if the train is 10km/h slower, it would take 3 more hours. What distance is the train covering?
Let distance be = X
let speed = Y
(X/Y) is the normal time taken
Now if speed is 10 km more
(X/Y+10) is the new time taken
(X/Y+10) - (X/Y) = 2
Now if speed is 10 km less
(X/Y) - (X/Y-10) = 3
Calculating we get
Y = 50 Km/Hr
Substituting for Y=50 we get
X = 600 KM
So distance is 600 Kms
Speed is 50 Kmph
Let distance be = X
let speed = Y
(X/Y) is the normal time taken
Now if speed is 10 km more
(X/Y+10) is the new time taken
(X/Y+10) - (X/Y) = 2
Now if speed is 10 km less
(X/Y) - (X/Y-10) = 3
Calculating we get
Y = 50 Km/Hr
Substituting for Y=50 we get
X = 600 KM
So distance is 600 Kms
Speed is 50 Kmph
adityaas11:
fantastic
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correct and is 600km
pls mark as brainliest
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