Physics, asked by rajpurohitmayank8205, 3 months ago

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Answered by tsaksham94189
0

Answer:

and is

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Answered by llpermissiontodancel
1

Answer:

"

Time of journey (free fall) = t = n seconds

Height of free fall = H meters ;

initial velocity = 0 ; acceleration due to gravity = g = 9.8 m/s²

Hn = (1/2) g t² = (1/2) g n² = distance travelled in n seconds

H(n-1) = (1/2) g (n - 1)² = distance travelled in n - 1 seconds

Distance travelled in the n th (last) second = h = Hn - H(n-1)

= (1/2)g {n² - (n - 1)²} = (1/2) g (2n - 1)

As per the question : h = (1/2) Hn

(1/2) g (2n - 1) = (1/4) g n²

=> 2n - 1 = n²/2

=> n² = 4n - 2

=> n² - 4n + 2 = 0

=> (n - 2)² - 2 = 0

=> (n - 2)² = 2

=> n - 2 = ± √2

=> n = 2 ± √2

=> n = (2 + √2) or (2 - √2)

n = 2 - √2, being less than 1, is rejected.

Time of journey = n = 2 + √2 seconds

Height of fall = (1/2) g (2 + √2)² = (1/2)(9.8)(4 + 2 + 4√2) = 9.8*(3 + 2√2) = 57.12 m

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