Question

give answer fast!!!iI

Answer 1

hey mate!!!

here is u r answer!!

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I hope help u✌️✌️

Answer 2

Hey Mate !

Here is your solution :

Given,

$ax {}^{2} - 2 \sqrt{5} x + 4 = 0$
Here,

Coefficient of x^2 ( a ) = a

Coefficient of x ( b ) = -2√5

Constant term ( c ) = 4

For any quadratic equation to have equal zeroes.


$b {}^{2} - 4ac = 0 \\ by \: putting \: the \: value \: of \: { \: a \: } \: {b} \: and \: c \\ ( - 2 \sqrt{5} ) {}^{2} - 4(4a) = 0 \\ \\ 20 - 16a = 0 \\ \\ 20 = 16a \\ \\ a = 20 \div 16 \\ \\ a = \frac{5}{4}$

Therefore, a = 5/4.

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Hope it helps !! ^_^