Question

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Answer 1

The mid-value of a class interval is 42. If the class-size is 10, find the upper and lower limits of the class.

ANSWER

⇒ Let upper limit and lower limit be x and y

⇒

2

x+y

=42 [ Given ]

∴ x+y=84 ------ ( 1 )

Now, according to the question,

⇒ x−y=10 ------ ( 2 )

Adding equation ( 1 ) and ( 2 ) we get,

2x=94

∴ x=47

And 47−y=10

∴ y=37

∴ Required class interval =37−47

Answer 2

Explanation:

hope u got it .......